1I cannot understand anything from this.Please if you like,then show me the detailed working or show that much with I can understand.
Let A be 2x2 matrix such that !A!=2 and B be 3x3 matrix such thatr !B!=3 and C be 4x4 matrix such that !C!=4.Then the value of
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13 Answers
1det(adj A)=(det A)(2-1)2=2
det(adj B)=(det B)(3-1)2=34
det(adj C)=(det C)(4-1)2=49
i think this can work !!
1
11i am also getting the answer as -2.
but i m not sure of the fact that...
l ABC l = lAl lBl lCl , which i have used...
@samagra,
det(adj A) = (det A)n-1. where n is the order of the determinant...
not (det A)(n-1)2.
1The answer is quite abject.The answer is -39.Please give the proof of your facts and logics.
1yes, ABC is not possible.
@joydoot,thanks.
is there any derivation for det(adj(adj(adj(...P times(adj(A)))..) for any K*K order matrix,if det(A) is given.
11then how to get it...
someone pls post how to get the solution of this problem..
yes, i know i cant do that,
l ABC l = lAl lBl lCl ..
11@ samagra,
for ur question,
lAl l adj A l = lAlk
thus, l adj Al = lAlk-1
thus similarly,
l adj(adj A) l = l adj A ln-1 = lAl(n-1)2.
thus for k th order determinant and p times adjoint determinant,
we get the result as,
l adj(adj(adj..........ptimes)))...)) l = lAl(k-1)p
11it is a theorem...
u can verify it...
take a determinant and find out its cofactors...
form another determinant by replacing the cofactors and then find out the product...
see what u get...