Algebra - Divisors

1

Philip Calvert ·2009-01-07 06:05:30

hi can you tell
is x_i is the set of all the divisors of n ?

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33

Abhishek Priyam ·2009-01-07 06:11:02

its the lang given in the question.. :(

But i think it should be all divisors...
I solved it in 11th but when tried it now for revision i am clueless :(

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33

Abhishek Priyam ·2009-01-07 07:26:18

Got it..

tx...

ignore this question...

[1]

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1

gagar.iitk ·2009-01-07 07:38:16

can u share ur ans

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1

Philip Calvert ·2009-01-07 07:42:51

ya it would help me

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341

Hari Shankar ·2009-01-07 07:53:34

Let S = x₁+x₂+...+x_n

Remember that if d is a divisor, then so is n/d.

2S = Î£1/x_i+Î£x_i/n = S + 75/n

Hence S = 75/n

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1

gagar.iitk ·2009-01-07 07:59:14

thanks

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33

Abhishek Priyam ·2009-01-07 08:06:51

[1]

Yes i got same answer and sorry 4 not replying as there was a power cut..

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1

Philip Calvert ·2009-01-07 08:08:56

how
2S = Î£1/xi+Î£xi/n = S + 75/n [7]

sorry if its stupid but got a mental block presently [2]

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33

Abhishek Priyam ·2009-01-07 08:12:04

x1.y1=n
x2.y2=n
..
.

so Î£1/xi=Î£yi/n

yi are also the divisors hence the answer..

Hope its clear..

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