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What is the coefficient of x65 in the expansion of (1+x)131(x2-x+1)130.

4 Answers

11
Subash ·

simplify it to (1+x)((1+x)(x2-x+1))^130

→ (1+x)(1+x3)^130

11
Subash ·

i think u can take it from there

62
Lokesh Verma ·

so basically u will have to take 2 different parts of it surbhi..

first when u take 1 then x so find power of x65 and x64

that is all :)

1
°ღ•๓яυΠ·

we hav 2 findd coeffcint of x^(64) in d second part n multiplyin wid x in fisrt trm we get wat we wan and we also gt 2 find coeffcint of x^(65) in second and multiplyin it wid 1 u egt wt u wan

u can do that by T(r+1)=nCr (a)^(n-r)b^(r)

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