how abt this approach!!
pl. post if u hav another mor elegant methd....
MY METHD :
LHS is modulus matlab "real"
RHS has 2b real..... ==> z has to be purely real!!!
so let z be a real no. x
then we get x2 = 2x - 1;
(x-1)2 = 0;
x= 1, y=0
|Z|2 = Z + Z - 1
FIND THE LOCUS OF "Z"
ANS given : point!!!
SORRY!!! ho gaya
thread open hote hi closed!!
how abt this approach!!
pl. post if u hav another mor elegant methd....
MY METHD :
LHS is modulus matlab "real"
RHS has 2b real..... ==> z has to be purely real!!!
so let z be a real no. x
then we get x2 = 2x - 1;
(x-1)2 = 0;
x= 1, y=0
argand plane par plot kar.....intersection pt ek hi hoga.............this is the qiuckest method....