functns

Let f (x + y) = f (x) f (y) for all x and y. Suppose that f (3) = 3 and f '(0) = 11. Then f ' (3) is given by :

opts are : 22,33,44, none of these....

Ans:
I'm getting 33 but the ans reads none of thes

35 Answers

33
Abhishek Priyam ·

are yaar .... aisa thode hi hai...

ans sab method se ana chahiye... ye maths hai chem nahi..[3]

i think theres no such continuous and differentiable function...

:P

33
Abhishek Priyam ·

lol... mera dimag aaj ghumne gaya hai....

phir se banate hai suru se...

1357
Manish Shankar ·

yeah that's what i wanted to point out

so λ=1

21
tapanmast Vora ·

ani already pointed it.... :(

but abhishek then ur functn cant b λe^(kx).....

i guess this type of sums shall b done widout assumin a functn....

ie the nishant sir has solved, makin use of the diff properties n given values of f(a)

11
Subash ·

ax does not satisfy for f'(0) as bhaiyya pointed out

so what is the function then [7]no need for this

24
eureka123 ·

yes it does not satisfy.........[7].......i think may be this part of question is wrong..[12].....

vaise bhi.......magic math has already written.."BUT ther r a NO. OF mistakes in it...."[1]

33
Abhishek Priyam ·

Question is wrong...

theres no such function...
[1]

11
Subash ·

no need to find the function so proceed like nishant bhaiyya has done and get the answer (:( which he says is wrong)

24
eureka123 ·

uffffffff[2]..............it was all over in 4th post.........and i started it again[9]

21
tapanmast Vora ·

hmmmm....

manish sir! in ur post da equality sign shud not equal to sign ne coz RHS we λ2 and in LHS sirf λ

33
Abhishek Priyam ·

Eureka is also right ax only satisfies f(x+y)=f(x)f(y) but it doesn't satisfies....other condition f'(0)=11

21
tapanmast Vora ·

I JUS LOVE THIS STATEMENT :

"ans sab method se ana chahiye... ye maths hai chem nahi"

21
tapanmast Vora ·

BUT HEY AB IF f'(0) exists n is equal to 11 it means its derivative exists.........

unless u consider it is non differentiable at x=3; which wud b toooo hard on the paper setter thodi daya karo us becherre par... [1]

11
Subash ·

"ans sab method se ana chahiye... ye maths hai chem nahi"

yes true but what is the method here other than bhaiyyas

checking for functions isnt a method

21
tapanmast Vora ·

subhash my connotation was to the statement in general.....

in this questn mayb ther doesnt existr a method.....

but the thot that in che n maths wenever 2 diff meth of solvign same sum exist then in math both lead to da same ans which is rarely the case in CHE....

SORRY CHEM LOVERS..... but i feel dats a fact

11
Subash ·

u dont need to say sorry (atleast to me bcoz im not a chem lover)

62
Lokesh Verma ·

There is no mistake in my solution..

because if you see closely, it is given differentiable at 3 just because it says f'(3) = something

and f'(0)= something else.

Remove x from my solution.. replace it by 3..
then do all the steps that I did..

It will work.

24
eureka123 ·

sorry to everyone........i made a compelete blunder.............Yes Nishant Sir is correct...............GOIIT IS WRONG....

1357
Manish Shankar ·

I have a little doubt
for f(x)=ax, is the condition f'(0)=11 true??

62
Lokesh Verma ·

oh din read the 2nd part of ur message..

Even I am getting 33...

Where is the question from :(

1
MAGIC MATH ROCKS ·

its actually frm goiit test carnival.....(4 IIT JEE)

BUT ther r a NO. OF mistakes in it....

abt 10 in BITSSAT paper alone

24
eureka123 ·

it is none of these dear...........
it is Cauchy'2 2nd equation
=> f(x)=ax

f(3)=3 =>a3=3 =>a=31/3

we have to find f'(3)
so first get f'(x)=axloga
=>f'(3)=31/3 (3)log31/3
=>f'(3)=log3 [1]

39
Dr.House ·

ya right eureka. AND MAGIC MATH U REMEMBER THIS, THE FUUNCTION SATISFYING THE GIVEN GIVEN EUATION IS ax.

sry

11
Anirudh Narayanan ·

But bhaiya just proved convincingly that it is 33.......so whose mistake is it...........bhaiya's and Magic Math's or goiit's?

24
eureka123 ·

i can only say that ans is log3....[2].......

i will try t ofigure out any calculation mistake here....[12]

11
Anirudh Narayanan ·

Bhargav.....santhusht?

39
Dr.House ·

hehehehe

62
Lokesh Verma ·

f(x)=f(x).f(0)

so f(0)=1

f(x+h)-f(x)=f(x){f(h)-1}

f(x+h)-f(x)=f(x){f(h)-f(0)}

divide by h and take limit as h tending to zero..

f'(x)=f(x).f'(0)

so f'(3)=3.11=33

33
Abhishek Priyam ·

Function is...

y=λekx where λ,k are constant..

where λk=11 and 3=λe3k..

11
Anirudh Narayanan ·

Arey yaar. Is proof to be given in accordance to the answer or the other way round?

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