minimum value.

The minimum value of
x2 + 2xy + 3y2 – 6x – 2y, where x, y are Real , is equal
to
(a) –9
(b) –11
(c) –12
(d) –10

8 Answers

262
Aditya Bhutra ·

ans -9 ??

1
fahadnasir nasir ·

The answar is (b)

1
rishabh ·

can some1 pls factorise this expression?

11
Devil ·

The given expression is (x+y)2-6(x+y)+2y2+4y≥-11

1
johncenaiit ·

pls explain why the expression is ≥ -11 ?

21
Shubhodip ·

i dont think there is an immediate conclusion from writing it as (x+y)^2-6(x+y)+2y^2+4y

other than (x+y-3)^2 + 2(y+1)^2 -11

:D

11
Devil ·

A quadratic whose leading coefficient is positive is minimised at x=-b2a.

(x+y)2-6(x+y)≥-9

same logic for 2y2+4y≥-2

sigh :-(

1
rishabh ·

can some1 pls post more sums of this type in this thread.
i have to improve my "factoisational" skills.

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