No. of solutions

Find the no. of real solutions of 2x4+1402-y4 =0

1 Answers

1057
Ketan Chandak ·

(y2+√2x2)(y2-√2x2)=1402=2 x 701
since both y2 and √2x2 will be always be positive for any real x and y....

y2+√2x2 =701
y2-√2x2 = 2

solving we get...
y2=7032 and x2=6992√2

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