positive integer solution

\hspace{-16}$How Many Positive Integer Solution $\mathbf{(a,b,c)}$ are\\\\ there to the equation $\mathbf{2004^a+2005^b=2006^c}$

7 Answers

1
ninepointcircle ·

very basic Diophantine trick is to check that both LHS and RHS should have same parity i.e both should be odd or both should be even

2006^{c}-2004^{a} = 2005^{b}
While LHS will always be even for positive integer a,b,c RHS will always be odd.
Hence no solutions.

:)

11
Sambit Senapati ·

Well, (a,b,c)=(0,1,1) is the only solution it seems.

1
Athenes Analyst ·

@Sambit
(0,1,1) implies 2005 = 2006!
Is it something like 2=1 (fallacy)

1
rishabh ·

@sambit,
he is asking for positive inegral solutions.

1708
man111 singh ·

thanks ninepointcircle

sambit for positive Integer solution

11
Sambit Senapati ·

oh sorry, I didnt notice.
@bond001-It doesnt imply 2005=2006

1
Athenes Analyst ·

Sorry I dint see properly!

No solutions! :)

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