Suppose you're on a game show and you're given the choice of three doors. Behind one door is a car; behind the others, goats [that is, booby prizes]. The car and the goats were placed randomly behind the doors before the show. The rules of the game show are as follows: After you have chosen a door, the door remains closed for the time being. The game show host, Monty Hall, who knows what is behind the doors, now has to open one of the two remaining doors, and the door he opens must have a goat behind it. If both remaining doors have goats behind them, he chooses one randomly. After Monty Hall opens a door with a goat, he will ask you to decide whether you want to stay with your first choice or to switch to the last remaining door. Imagine that you chose Door 1 and the host opens Door 3, which has a goat. He then asks you "Do you want to switch to Door Number 2?" Is it to your advantage to change your choice?
13well, interpreting d situation, we get 2 cases...
case 1 : if d door chosen by us has d car...
den d host has 2 ways of choosing d door dat has goat behind it...
case 2 : if d door chosen by us has d goat...
den d host has only one way of choosing d door dat has goat behind it...
since, d probability dat d third left-out door has goat behind it is more, its not much to our advantage to change d choice...
13The Monty Hall problem is a probability puzzle based on the American television game show Let's Make a Deal. The name comes from the show's host, Monty Hall. The problem is also called the Monty Hall paradox.
13http://en.wikipedia.org/wiki/Monty_Hall_problem
see this!!!#@!!%%!@#!%@%!%!
13http://www.usd.edu/~xtwang/Papers/MontyHallPaper.pdf
