probablity2

If 10 things are distributed among 3 persons,the chance of a particular person having more than 5 of them is 1507/19683

1 Answers

62
Lokesh Verma ·

wow that is some fraction!

each one getting less than 5

1+4+5 = 10C1. 9C4. 3! = (10.9.8.7.6) / 4
2+4+4 = 10C2. 8C4. 3 = (10.9.8.7.6.5)/16
2+3+5 = 10C2. 8C3. 3! = (10.9.8.7.6) /2
3+3+4 = 10C3. 7C3 . 3 = (10.9.8.7.6.5)/12

Now try to get this one...

Your Answer

Close [X]