1
mohit sengar
·2011-04-04 03:41:43
no of elements in m = 6 and n = 3
21
Shubhodip
·2011-04-04 06:01:43
It's clear that the first set has 2m subsets and second one has 2n subests.
so we have to solve 2m - 2n = 56 (m,n are positive integers)
Its also clear that m>n
let m = k+n
so 2k+n- 2n= 56
2n(2k- 1)= 23*7
clearly 2k-1 is odd
so 2n= 23, and n = 3
and 2k-1= 7 so k =3
so m = 3+3 = 6 and n = 3
;O)
36
rahul
·2011-04-04 08:04:24
Thanks shubhodip bhai! I worked it out by hit and trial method but ur's have some logic.
6
AKHIL
·2011-04-05 04:50:43
hit and trial se ho gaya na!!
bas theek hai!!
:P
but good job shubhodip....:)