1@nishant bhaiya p>2 not less tnan 2
stat1: if p is chosen at random from the interval [0,5] then the pblity of the eqn x2+px+(p+2)/4=0 having real roots is 2/5
cozzz
stat 2:for real roots either p<= -1 or >=2
ans is d i can get da 2nd one
so pl explain only the 1st 1
-
UP 0 DOWN 0 0 10
10 Answers
62p2>p+2
p2-p+1/4>9/4
(p-1/2)2>(3/2)2
-3/2>(p-1/2)>(3/2)
-1>p>2
going to die out of shame ;)
so the prob is 3/5 *(corrected after richa's comment)
