ques doubt

x ² + 6 x + y ² = 4

Or , ( x + 3 ) ² = 13 - y ²

For " x " to be an integer , " 13 - y ² " must be a perfect square , which can happen only for -

y = 2 , - 2 , 3 , - 3 ................ Accordingly , " x " will also take different values .

Hence , there are 4 ordered pairs of ( x , y ) .

then there will be 8 solns..pls confirm

-1,2
-1,-2
-5,2
-5,-2

and 4 more with y=+ -3

All the solutions are -

( - 1 , 3 ) ; ( - 1 , - 3 ) ; ( - 5 , 3 ) ; ( - 5 , - 3 ) ; ( 0 , 2 ) ; ( 0 , - 2 ) ; ( - 6 , - 2 ) , ( - 6 , - 2 ) ;

Hence , there are 8 solutions .

EDIT - Thanks to " Seoni " , I corrected a major blunder . And Seoni , thanks to you mate for giving me a question worth trying .

add to ur list
-6,2
-6, -2......hence 8,,,

thanks for giving time...