roots

real roots of the eqn 7log7(x2-4x+5)=x-1 are

5 Answers

62
Lokesh Verma ·

This is a quadratic equation.. solve it :)

take 7log7 = k and proceed !!

1
dimensions (dimentime) ·

x2-4x+5>0 (D < 0)

it can also be written as

x2-4x+5 = x-1

as alogax = x

x2-5x+6 = 0

=> x = 3,2

& x - 1 > 0

=> x > 1

so final ans,

x = 3,2

62
Lokesh Verma ·

huh!!
what's the question :O

!!!!

1
dimensions (dimentime) ·

i think it is log to the base 7

not log7.............................

62
Lokesh Verma ·

oh.. ok.. got u..

:)
good work :)

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