2621) yes, i think you can
2) write 1 in the numerator as (2-1) , (3-2), ....
the terms will cancel out
ans will be 1
3)the AM of the 9"AM's" = AM of 2 and 24
or, sum of "AM's" /9 = (2+24)/2
or, sum of AM's = 9*13=117
1)In an AP, Sn = n2p,Sk = k2p ; k,n,p are natural numbers and k≠n
Sp = ?
can we answer p2p just by seeing the pattern?
2) 11x2+12x3+13x4+,,,,,,,,, to n terms
3)Sum of 9 AM's between 2 and 24 is _____
4)If a,b,c be respectively pth,qth and rth terms of a GP, then
(q-r)loga + (r-p)logb + (p-q)logc = ____
5)If the positive numbers a,b,c are in AP, then 1√b+√c, 1√c+√a,1√a+√b are in _____
6)a,b,c are positive numbers in GP and loga-log2b,log2b-log3c,log3c-loga are in AP,then a,b,c are lengths of sides of a triangle which is
(acute angled but not equilateral,obtuse angled,right angled,equilateral,none of these)
-
UP 0 DOWN 0 0 7
7 Answers
262
716. Using the given information and sine angle formula in a triangle, I got the sides as 9,6,4.
So, According to me, It comes out to be an Obtuse angled triangle
5. I think they are also in AP. Just Check for the condition of being in AP of the given expression.
4. Take the first term to be ' m ' and common ratio to be ' d '.
Hence, Tp = m(p-1)d ; Tq = m(q-1)d ; Tr = m(r-1)d
Put in the given expression to yield the answer as ' 0 '
- Akash can u explain q 4Upvote·0· Reply ·2016-04-19 08:21:44
1@vivek, you won't get the sides as 9,6,4 it is 9:6:4
but how did you conclude that it is obtuse angled ?
262@ john - let sides be 9k,6k,4k
now (9k)2>(6k)2 + (4k)2
hence it is obtuse
1i don't know the property used by you,,,,so if it was "less than" then acute, and "equal" then right angled ,,,,like that?
