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Solve
x1/3+(2x-3)1/3=(12(x-1))1/3

10 Answers

62
Lokesh Verma ·

t=3x-3
t/x = 3-3/x

x1/3 + (t-x)1/3 = (4t)1/3
1+ (t/x-1)1/3 = (4t/x)1/3

taking cube

1+ 3(t/x-1)1/3 + 3(t/x-1)2/3 + (t/x-1) = 4t/x

3(t/x-1)1/3 + 3(t/x-1)2/3 = 3t/x

(t/x-1)1/3 + (t/x-1)2/3 = t/x

(t/x-1) + (t/x-1)2 +3(t/x-1)(t/x) = (t/x)3

(t/x-1) + (t/x-1)2 +3(t/x-1)(t/x) = (t/x)3

(t/x-1)t/x +3(t/x-1)(t/x) = (t/x)3

4(t/x-1)(t/x) = (t/x)3

Thus , t/x=0 or

4(t/x-1) = (t/x)2

(t/x)2 -4t/x +4 =0

t/x=2

thus solved :)

62
Lokesh Verma ·

t/x = 3-3/x

3-3/x= 0

x=1

3-3/x =2

3/x=1

x=3

so x=1, 3 are the solutions!

24
eureka123 ·

Thanks for reply..
Just one question.:: Can these type of questions come in JEE ?? I mean to say that should I practice more of such type or not. ??

62
Lokesh Verma ·

frankly i think i have messed up the solution.. so it is looking dirty and tough..

JEee will have more simpler problems (or which are solved in lesser no of steps.!)

62
Lokesh Verma ·

x1/3 + (2x-3)1/3 = (12x-12)1/3

take cube

x+2x-3 + {x(2x-3)}1/3{x1/3 + (2x-3)1/3} = 12x-12

thus,

x+2x-3 + {x(2x-3)}1/3 (12x-12)1/3= 12x-12

thus,

{x(2x-3)}1/3 (12x-12)1/3 = 9x-9

Now this is simple? (oops simpler?)

To try to make the solution simple, i made it more difficult :D

341
Hari Shankar ·

Let a = x1/3 and b = (2x-3)1/3

Then the equation is

a1/3+b1/3 - 41/3(a+b)1/3 = 0

We know that if p+q+r =0, then p3+q3+r3 = 3pqr

Hence a+b-4(a+b) = -3.(4ab)1/3(a+b)1/3 or

(a+b) = (4ab)1/3(a+b)1/3

Now either a+b = 0 i.e. x = 1 or

(a+b)2/3 = (4ab)1/3

Cubing both sides, we get

(a+b)2 = 4ab or (a-b)2 = 0 or a = b

Hence x = 2x-3 giving x = 3 as the other solution

62
Lokesh Verma ·

great man ....

I was trying to simplify it.. and made a big mess of it :D

Godo that you simplified it :)

341
Hari Shankar ·

There are several of these kind of problems. One that comes to mind immediately is:

Solve (6-x)4+(x-8)4 = 16

Unless you spot that this method can be used, it will be a very messy problem.

I will see if I can hunt down other problems of this variety

341
Hari Shankar ·

and since this is eureka's thread I want to just say that see we will be eager to help you out bcos u r a bro (applies to sis also) who is on the same path. But when we put effort and then no one says a thing it will be like wasted. Now Nishant brother said something so it makes me look if i can add something more. You get more cooperation just by being nice

341
Hari Shankar ·

Ok a similar problem:

Solve (x2+x-2)3+(2x2-x-1)3 = 27(x2-1)3

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