111) √10+(√5-√3)√10-(√5-√3).
=[√10+(√5-√3)][√10+(√5-√3)][√10+(√5-√3)][√10-(√5-√3)].
=18-2√15+10√2-2√302(1+√15)
we have to rationalise it again with (1-√15).
3 Answers
11
262for 2nd case- the expression can be expresed as - (√3 )3 + (√2)3 + 3.√2.√3( √2 +√3 )
hence it is in the form of (a+b)3
or (√2 +√3)3
therefore its cube root is just - √2 + √3
