Triangular world

Find LF - LE ???? thank you

12 Answers

1
Abhisek ·

ΔABC ~ ΔEFD (AA Similarity)
So,
LF=LB=101°
and
LE=LA=30°
LF - LE = 101° - 30° = 71°

36
rahul ·

But how can u make both of them similar...??
Do they look similar?
i don't think so.....!!
This problem is that that simple as u r taking it to be..
Theres a short-long thing inside it... which is gonna explore a big thing...!!
Which is 'a must know' but we dunno...!! :D

11
Soham Mukherjee ·

From THE SSA rule....ABC is CONGRUENT.to DEF..(the image is not right...but it may be assumed).
then...ang.F=ang C
ang E= ang A
Ang f-Ang E=101°-30°=71°

11
Soham Mukherjee ·

please correct the figure
...

1
Abhisek ·

@ Soham : I dont think there was any SSA Congruency Criterion for triangles...was there ? [7]

1
EmInEm ·

rotate 1st triangle such that C coincides with D, A with E and B with F

so angle A = angle E = 30

F = 180 - 49 - 30

so F - E = 180 - 49 - 60 = 71

1
ninepointcircle ·

well as the question cant be directly done by congruence and similarity (i mean you have to make some constructions which make such an easy question tougher) i present my trigonometry solution.

Firsdt of all angle ABC = 101°

using Sine rule in triangle ABC we get

sin49AB = sin 101AC........(1)

using Sine rule in triangle DEF we get

sin49EF = sin DFEDE............(2)

As DE= AB , (1) =(2)

from which we get
DEF = 101
and then DFE= 30 ( by angle sum property)
therfore LF - LE = 71°

:)

36
rahul ·

@every1 - i said naa... therez a small but big thing to be revealed...

generally we all know only five criterions for congruency of triangles...

1. SAS
2. SSS
3. AAS
4. ASA
5. RHS

but in any of my 'upto 10th' level book i haven't found any criterion
like 'SSA' though there's a proof for it...

In the given triangles ABC and DEF we have been given that,

AB = DE , AC = DF and, LC = LF

Now, to prove, [ABC] = [DEF]

Now, we drop perpendiculars from A and D on BC at EF at M and N respectively...

Now, from triangles AMC and DNF we have,

LAMC = LDNF , AC = DF and LACM = LDFN

thus, [AMC] = [DNF] by AAS criterion..
=> AM = DN (c.p.c.t)

Again, in triangle AMB and DNE we have,

LAMB = LDNE = 900

AM = DN and AB = DE

Thus, [AMB] = [DNE] ..... by RHS criterion...

Thus, [AMC] + [AMB] = [DNF] + [DNE]

=> [ABC] = [DEF] proved...

Hence, SSA is in a crition for congruency of triangles..

Do remember it as well... :D

Be true!! Did u know that?

But why aren't we taught this...??

vote : ...... not lol

36
rahul ·

so clearly,

/\ BAC ≡ /\ FED [by SSA - criterion]

Thus, LF = LB and LE = LA

i.e., LF = 180° - (30° + 49°) = 180° - 79° = 101°

And, LE = 30°

And hence, LF - LE = 101° - 30° = 71° Ans.

1
kunl ·

yosycho![3][3]

6
AKHIL ·

the ans is 71........

and i think its NCERT quesn!!!
isnt it??

36
rahul ·

nopes... i don't think so...!!

There is no such problem in NCERT... i guess...!!

The only thing which can kill such problems is the concept of
SSA or at last contruction... like drawing a perendicular nd all...!!

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