value of (a,b,c) in cbic equation

\hspace{-16}$Calculation of real values of $\bf{(a,b,c)}$ such that $\bf{x^3-ax^2+bx-c =0}$\\\\ has a roots $\bf{a\;,b}$ and $\bf{c.}$

1 Answers

1357

Manish Shankar ·2013-09-19 05:46:34

a+b+c=a
ab+bc+ca=b
abc=c

which gives
a=-1
b=-1
c=1

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