very easy...

subash...can this 12! be done??

virang din get u :(...explain a bit...

i got 3^12...don know if it is rite

luk each apple has got 3 choices so 3¹²...but it doesnt end there as he wants each boy to recieve atleast one apple...so we'l have to discard all cases in which the boys donot get atleast one apple each...for that we concider 2 different cases,
1) in which 1 boy doesnot any apple
2)2 boys donot get any apples..
for the 1st one we have
³C₂*(2¹²-2) ways
for the second we have
³C₂ ways
so the final answer shud be the initial one -(cases where u donot have justice done to every one)
=3¹²-(3(2¹²-2)+3)
cheers!!

without any restrictions, each fruit has three choices so number of ways = 3^{12}
Now if one boy does not get any fruit then the number
of ways = ^{3}C_{2}.2^{12}
now if two do not get any fruits then the number of ways =
^{3}C_{1}.1^{12}
Now if none of them get no fruits then number of ways = 1
So, by principle of inclusion and exclusion the answer
is = 3^{12} - ^{3}C_{2}.2^{12} + ^{3}C_{1}.1^{12}-1