YG ii 23 maths

2^l+3^m+5ⁿ
=2^l+(4-1)^m+(4+1)ⁿ
=2^l+ multiple of 4+(-1)^m+1ⁿ

here for l=1 m=2,4,6,8

4x8=32ways

for l≠1 m=1,3,5,7

7x4x8=224 ways

so option d

well i didnt get >>>
for l≠1 m=1,3,5,7

7x4x8=224 ways

<<<

please make me understAND dis step [76]

well some one make clear about the steps nt getting it!!!

observe dat l,m,n ε [1,8]

in d first case when l=1, m can take 4 values viz., 2,4,6,8... and n can take 8 values viz.,1 to 8... so no. of ordered triplets = 4x8 = 32

in d second case when l≠1, l can take 7 values viz., 2 to 7... m can take 4 values viz., 1,3,5,7... and n can take 8 values viz., 1 to 8... so no. of ordered triplets = 7x4x8 =224

hence answer is 224+32=256... option D........