another one

I1=Π/6∫Π/3sinx/x

I2=∫(same limits )sin(tanx)/tanx

I3=∫(same limits)sin(sinx)/sinx

give the relation between I1 I2 and I3

7 Answers

3
msp ·

I3>I1>I2

3
msp ·

can u give the soln moon

3
msp ·

kkk

11
Subash ·

I3<I1<I2

11
Subash ·

please sum one post solutions

341
Hari Shankar ·

The function f(x) = sin x / x is a decreasing function on [0, π/2].

Also tanx > x > sin x in the given interval.

Hence sin(sin x)/ sin x> sin x/ x > sin(tan x)/tan x

Hence I3>I1>I2

11
Subash ·

thank you sir

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