33just for fun u can see this graph although no relation from finding its area ;)
thats for a>0.... betters say a=1
13 Answers
62Read this one... this is very very similar
http://targetiit.com/iit_jee_forum/posts/area_931.html
33
62r=a(1+cosθ),0<θ<2π.
dA=1/2r2dθ (See the post on the link above for complete explanation..)
Area= ∫1/2a2(1+cosθ)2dθ
= ∫1/2a2(1+2cosθ+cos2θ)dθ
= ∫1/2a2(1+2cosθ+(1+cos2θ)/2)dθ
This should give u the answer when integrating from 0 to 2pi :)
1i have a question... is this there in iit syllabus??
jus say -> 'yes' or 'no' . :P
1well its a part of polar coordinates (not a part of syllabus:))
but it was not difficult & u hav to study it in 1st year( but then we hav formulas to find it:))
62This is not in syllabus sky..
dont worry about this part :)
even though this makes the solutions at times much simpler.. .like even the most trivial case of finding the area of a circle...