Daily Graph 19-0-2010

i cant get the ans ...someone please show it!!!

the part of curve in IIIrd quadrant is the inverted image of part of curve in Ist quadrant

i don't think the graph exists in 2nd quadrant
there is no -ve value of x for which y is +ve so the graph can't exist in 2nd quadrant

you also confirm this from othersas i am not so good in graphs

what if x=0?

at x=0 it f(x) will be ∞ because curve is not defined

take
lim x+1/x
x→0

which equals infinte
if i solved correctly...:P

i agree to the fact that it exists in 3rd and 1st quad...
my prob is
am not geting theCURVES alright...
can someone help

rather tanuj's post must be pinked ...very nice and precise graph

well i never found that x=y can also be a asymptote!!

or simply say

\lim_{x\rightarrow \infty}f(x)=x