1the transformation x→1x helps doesnt' it
$Calculate $\int_{0}^{\infty}\frac{tan^{-1}(\frac{x}{3})+tan^{-1}(3x)}{1+x^2}dx$ =
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3 Answers
1post this in olympiad section [6] That section has been created for u
39@ above poster : Look at the difference in posting times..do you have no life? You just like going through his posts and writing useless comments on his threads. Bohot zyaada pyaar aa raha hai uske liye? What are you, gay?
Announcement : The idiot above me is not me. Please do not think of it as my second account. I have better things to do.
@man111 : I think it involves using an inverse tan substitution, coz the denominator is 1 + x².
