11f` = 2x + a
f`>0
2x + a>
a>-2x
First 1
a>-2
a = -2
wat is the minimum value of 'a' such that the function f given by f(x)=x2+ax+1 is strictly increasing on (1,2)
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4 Answers
24since strictly increasing....
=> f(2)>f(1)
=>4+2a+1>1+a+1
=> a>-3
=>amin=-2
1but virang1
if x=2 then a= - 4(<-2)
and also x is given in the open interval 1 to 2