1why??
if f(x)=(|x|(3 e1/|x|+4))/(2- e1/|x|) for x≠0
nd f(0)=0 then
a)f is continuous
b)f is continuous but not diff at x=0
c)f'(0) exists
d)f'(0+)=2
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4 Answers
62see the derivative of such problems can be done by a small trick..
i mean when |x| is involved!
take the limit of the derivative at the x=0
if it is not zero it is not differentaible!
(think why!)
dont learn this as a fact!
24sir can u xplain what u said..........i too cant get it........
aise functions ka derivvative kya lena theek hoga????????[7][12]
62sorry i din see this one..
yes it will be ok..
see here take the derivative of
if f(x)=(x(3 e1/x+4))/(2- e1/x)
and take the derivative wrt x! see if it is zero as x converges to zero!
If it is not thenit wont be differentialbe!
why?
Reason is that the graph is an evenfunction. So its slope will be symmetric. about the origin.
so soon after 0 if the slope is 1 thenjust before 0, the slope will be -1!
hence LHD will nto be equal to the RHD.