honey's Question

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Q
I = ₀âˆ«^Ï€ log(1+cos x)dx

#Mathematics #Calculus

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6 Answers

1

Philip Calvert ·2009-01-17 10:55:21

my soln

I = ₀âˆ«^Ï€log(1-cos x)dx

2I = ₀âˆ«^Ï€ log sin²x dx

I = 2 ₀âˆ«^Ï€/2 log sinx dx

ab ho jayega
i think now it is easy !!

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1

Philip Calvert ·2009-01-17 10:58:17

the original question can be viewed at
http://targetiit.com/iit_jee_forum/posts/integration_1419.html

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3

msp ·2009-01-17 11:00:16

i dont know wat u r doing u r posting the question u itself posting its solutions

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1

Philip Calvert ·2009-01-17 11:01:02

hey i wrote it was honey's question not mine

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MAK ·2009-01-17 11:09:14

well, ur solution has many mistakes philip...

if dis is d question... I = ₀âˆ«^Ï€ log(1+cos x)dx

then d soln. is... I = ₀âˆ«^Ï€log(2cos²(x/2)) dx

I = ₀âˆ«^Ï€log2.dx + 2₀âˆ«^Ï€log(cos(x/2)).dx

from this, it can be solved...

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msp ·2009-01-17 11:10:32

sry if it hurts u philip..

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Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

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