integrate....definite..

I= 0∫3 ([x] +[x+1/3] +[x+2/3]) dx

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62
Lokesh Verma ·

the first part or red is between 1/3 and 2/3

the part between 0 and 1/3 is 0..

now try.. :)

first one has height 1 .. 2nd height 2 .. so on..

answer 1/3{0+1+2....8} = 12

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