integration

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F(x)=f(x)+f(1/x),whr f(x)=âˆ«₁^x logt dt/1+t
Then F(e) equals?

#Mathematics #Calculus

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8 Answers

39

Dr.House ·2009-04-20 07:57:15

answer is 1

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1

Honey Arora ·2009-04-20 08:01:17

ans is nt 1

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11

Mani Pal Singh ·2009-04-20 08:03:14

i think this could help

http://targetiit.com/iit_jee_forum/posts/to_santom_p_828.html

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39

Dr.House ·2009-04-20 08:05:11

sorry.

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39

Dr.House ·2009-04-20 08:06:37

no manipal. see correctly. no link with link u gave and the question

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1

Honey Arora ·2009-04-20 08:09:01

thtz really sm other thing
see if u cn give itz soln....i need it

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1357

Manish Shankar ·2009-04-20 08:19:56

f(1/x)=âˆ«₁^1/xlogtdt/(1+t)

put t=1/m

f(1/x)=âˆ«₁^xlogmdm/m(1+m)=âˆ«₁^xlogtdt/t(1+t)

F(x)=âˆ«₁^xlogtdt/(1+t)+âˆ«₁^xlogtdt/t(1+t)=âˆ«₁^xlogtdt/t

now you can find F(e)

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1

Honey Arora ·2009-04-20 08:26:04

got it......thx

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Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω