intregal....1

∫llog xx1/2

upper limit 1
lower limit 0
form the positive side

3 Answers

262
Aditya Bhutra ·

take x = t2

1
Ayush Shaw ·

thats a way but ln 0 has no value

262
Aditya Bhutra ·

I = \int_{0}^{1}{\frac{log(x)}{\sqrt{x}}}dx

let x =t2 ; dx = 2tdt

I = 4\int_{0}^{1}{{log(t)}}dt

I = 4\left<t(log(t)-1) \right>^{1} _{0}

now , \lim_{x\rightarrow 0} xlogx = 0

I = -4

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