limit

limn→∞ (n!/(nk)n)1/n

please do solve this even if it seems simple

i don't think answer should be 1/(2k) but if you get this somehow it'll be very interesting

39 Answers

33
Abhishek Priyam ·

1/2k

[3]

13
Двҥїяuρ now in medical c ·

what is 0∫1ln x dx???

21
tapanmast Vora ·

solv it by parts.... lnx = u ; 1=v

21
tapanmast Vora ·

sum1 reply yaar, CMON!!!!!!

13
Двҥїяuρ now in medical c ·

but how can u put the limits??....ln 0=∞

11
Subash ·

so is it non integrable in the given limits

because it is discontinuous

21
tapanmast Vora ·

INTERESTIN.....

BUT I THJNK THE BOUNDIN VALUES R NTO 2 B COUNTED.....

SOLVE THIIS IT'LL B CLEARER...

0∫2π [sin(x)] ∂x

wer [.] denotes gr8est int.

{HINT : FOR WAT RANGE WILL U INTEGRATE FOR [sin(x)] = 1 ???? [7] }

11
Subash ·

[7]
[7]
[7]

21
tapanmast Vora ·

dont think much....

ther is no value/range for which u will b integratin [sinx] = 1;

thats y i said ignore the limits though v sub them while solving general int. sums.....

coz in 0 to π/2 [sijnx] = 0;
its jus at dat 1 infinitesimal pt that [sinx] = 1;

therfor v do not find any range for [sinx]=1;

HOPE U GOT MA PT

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