limit.........making me mad.....

the answer to this 1 is Cos a

are u guys using LH ???????????

i dont answer by that method then beocz it would be toooo long..........

give some other good method if u have......

log(1+x)=x-x²/2+x³/3-x⁴/4.........................

now replace x by x-a-1
and denominator mein x by e^x-e^a-1

upper niiche kat jayega
and hence ur answer !!!!!!!!!!!!!

yup, same contoversy with

\lim_{x\rightarrow 0}\frac{sin\sqrt{x}}{\sqrt{x}}

more appropriate question shud have been lim(x→a+) i think... btw if this came in JEE then what shud be the answer.. if it was x→a doesn't exist or will it be cos(a) ?