limits

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#Mathematics #Calculus

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7 Answers

1

Euclid ·2010-10-28 19:41:02

yes all the three exist...
1) -2
2) âˆ©/2
3) 1

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23

qwerty ·2010-10-29 03:36:24

lim_xâ†’-1 sin^-1x also exists ,and the limit is - Ï€/2

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6

AKHIL ·2010-10-29 07:05:29

ya
rite
all of them exist...

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1

Euclid ·2010-10-29 19:47:45

:)

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11

sagnik sarkar ·2010-10-29 23:57:29

@Querty But lim_x-->-1(-)sin(inverse x) doesnt exist, i.e LHL doesnt exist as it is not in the domain of sin(inverse x).

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1

Euclid ·2010-10-30 10:23:00

jo domain mein nahi hai y to consider???

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23

qwerty ·2010-10-30 19:52:41

xâ†’ -1⁺ is in domain
xâ†’ -1^- isnt in domain itself

so wen we are taking limit xâ†’ -1, we consider xâ†’ -1⁺ only

u draw graph of sin^-1x , and see wat does sin^-1x tend to wen x tends to -1

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Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

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