1Anrwer is 0.
As lim (x→0), sin x≈x and tan x≈x.
.: it becomes lim (x→0) x log x
Above form is 0 X ∞, convert it into ∞/∞ and use L' HOSPITAL RULE. You will get the answer.
3 Answers
1
262i think limit does not exist
since for x→0- sinx will be negative and the logarithm wont be defined
