limits...

3 Answers

1
RAY ·

anyone..reply.......

1
dimensions (dimentime) ·

ok let me give u a hint
just write the expansion of LHS

2-1tan(x/2)+2-2tan(x/22)+.......+2-ntan(x/2-n) =S

now add cotx on both side, on lhs write

cotx = (1-tan2(x/2))/2tan(x/2)

& go on simplifing, u will get a definite pattern

at last u will get

lim n-> infty 2-ncot(x/2n)

which gives limit as 1/x

so the limit S = (1/x) - cotx

:)

1
RAY ·

waw..nice...dimensions.........

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