3x1 = 2cos(pi/12)
x2 = 2cos(pi/24)
xn = 2cos(pi/(6*2n))
now
√2-xn = 2sin(pi/(6*2n+1))
so it simplifies to
lt 2n+2sin(pi/(6*2n+1))
n->∞
kinowing as A->0 sinA->A ..................
2n+2pi/(6*2n+1)
= pi/3 !!!!!!!!!!!!!
forgive calc errors!!!!!!!!!!!!!!