LIMITS rockz CALCULUS :) prob solve nd explain

Q1)multi ply a^n num and denom.....

U get α^2n/sinx/ + cos x/(α^2n +1)

lim a tends to 1+ and n tends to Infinity means a^2n tends to 1
therefore a={/sinx/+/cosx/}/2

But lim a tends to -1 and n tends to inf. =0

so b=/cosx/

For c use cosθ+cos2θ+cos3θ..... cosnθ= { sin(nθ/2)/son(θ/2)}*cos ((n+1)θ/2)

got it folks.....

this was easy question manipal bhai itna darte kyun ho sawalon se...chak de phatte

but double limit never came in IIT

yaar main darta nahin hoon
read the bolded statement in #5

it was nt very tough aur yeh to nahi likha hai ki dble limit aa nahi sakti may be it start cming frm dis year

do baar limit mat nikalo.....n--->∞ ko uper likh do...and then rest of limit ko solve kar do..
....do baar lt likh dene se question out of syllabus nahi ho jata.

sorry manipal if got offended but i dont think u will be...:) cheers

and richa post how did u solve for c??(weak in trigo)

ma ans is crt bt no pink :(

[15] [14] [13] to priyam [3]

19) [0,1]

bhai
yeh tuune kya kiya?????

SITE KA NAAM HAI

TARGET IIT

IIT mein tere se aise sawal koi nahi poochega
better not waste 10 ( useful 4 JEE)concepts to make 1

manipal how knw its not in JEE ?

there r 25 years paper available in the markets
u can get a guess about the type of ques they ask

IN MY WHOLE EXPERIENCE OF 2 YEARS WIHT TEACHERS BOOKS AND PAPERS
I HAD NEVER SEEN SUCH TYPE OF PROBLEM

IF SOMEONE CAN SOLVE I WILL BE THANKFUL

a=[sinx] b=[cosx]c=1/√2[]=mode

q18 allR