limits;-

\lim_{n->infinity} \frac{1}{2n}[log(2nCn)]

11 Answers

11
Mani Pal Singh ·

did u apply l hospital usse sidha hi aa raha hai!!!!!!!!

1
skygirl ·

but i think that will become messy ...

u have ne other 'sophisticated' method ?

21
tapanmast Vora ·

sky ye limit of sum se ho jaega ........

that 1/n outside will act dx

is the answer 0.5 ln2 ??

11
Mani Pal Singh ·

idea sir ji (madam ji):P

apply the expansion of logx

1
skygirl ·

yes tapan! fantastic! i forgot abt the limit of sums... thanx for reminding!

1
skygirl ·

@ mani, idea kuchh kharab nahi hai .... sochte hai..

21
tapanmast Vora ·

SKy n Mani : wen's ur BITS??

11
Mani Pal Singh ·

bhai no bits 4 me
only PITS

1
skygirl ·

my BITS on 18th may ... kolkata center.. urs ?

21
tapanmast Vora ·

Wow!! me too on 18th May .......... Ahmedabad ..........

@ mani : y din u opt 4 BITS ??

66
kaymant ·

The answer: \ln 2

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