R U INTELLIGENT?? THEN TRY THIS...

JEE Main Guidance › Calculus questions › R U INTELLIGENT?? THEN TRY THIS...

âˆ«mod(sinx+cosx)

#Mathematics #Calculus

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8 Answers

62

Lokesh Verma ·2009-03-04 05:33:40

Indefinite integral, I think there will be lots of cases..

You cant comment just like that.

Atleast I cant!

Definite integral, this makes more sense :)

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skygirl ·2009-03-04 05:38:43

\int \sqrt{2}\left|\frac{1}{\sqrt{2}} (sinx+cosx)\right|dx

=> {\color{red} \int \sqrt{2}|sin(x+\pi /4)|dx}

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1

pavanmalhra ·2009-03-04 05:42:08

ACTUALLY THE ANS IS IN SIGNUM FORM

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skygirl ·2009-03-04 05:45:43

signum not in jee !!

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pavanmalhra ·2009-03-04 05:59:06

THE CORRECT ANS.. IS (sinx-cosx)sgm(sinx+cosx) BUT HOW??

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62

Lokesh Verma ·2009-03-04 06:02:01

hmm.. this is ok..

this is a small trick..

try to think for a minute.. I think you will be able to understand :)

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pavanmalhra ·2009-03-04 06:10:03

I M STILL NOT ABLE TO UNDERSTAND

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11

Mani Pal Singh ·2009-03-15 09:02:05

THIS BECOMES âˆ«√2|SIN(X+âˆ©/4)|

this have to be done by making a lot of cases like(-âˆ©/4toâˆ©/4,âˆ©/4to3âˆ©/4...............)

look u have to take cases and in the end generalize it with 2nâˆ©

if sill not clear do ask again

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Your Answer

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° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω