\hspace{-16}$If $\mathbf{I_{1}=\int_{0}^{1}(1-x^4)^7dx}$ and $\mathbf{I_{2}=\int_{0}^{1}(1-x^4)^6dx}$\\\\\\ Then $\mathbf{\frac{29}{4}.\left(\frac{I_{1}}{I_{2}}\right)=}$
-
UP 0 DOWN 0 0 1
1 Answers
17
use by parts for I1 => I1 = 28 ∫ (1-x4)6 . x4
=> I2 - I128 = I1
=> I1I2 = 2829 \Box
