simple but stil...........

For what values of λ does the function f (x)=(λ+2)x3−3λx2+9λx−1 decrease for all x?

11 Answers

1
The Race begins... ·

f'(x)=3(λ+2)x2-6λx+9λ

f(x) decreases => f'(x)<0 for all x

=> (λ+2)x2-2λx+3λ<0

now find the solution set of x in the above inequality and then the values of λ can be found.

:)

11
Mani Pal Singh ·

yar itna to mujhe bhi aata hai [2]

i am asking 4 an answer as my answer is not matching[1]

1
vector ·

may be u misssed d case wen it wud be a non quadratic

11
Mani Pal Singh ·

NOPE
NO MISSING ON MY SIDE
PLEASE GIVE THE SOLUTION[1]

66
kaymant ·

\lambda <-3

11
Mani Pal Singh ·

sir ji tussi hamesha di tarah perfect ho
but in the last step

we got

2λ2+6λ>0

so in this what we will take in the interval
λ<-3 and λ>0
or
λ<-3 or λ>0

66
kaymant ·

There is one more constraint. The coefficient of x2 i.e. λ + 2 < 0. This wont be true for λ>0.

1
vector ·

der is one more cndition na λ+2<0

11
Mani Pal Singh ·

sir i got

NO SOLUTION

PLEASE CHECK UR WORK AGAIN
BUT AS THE ANSWER GVEN IS NOT MATCHING AS USUAL

PLEASE SHOW ME THE LAST STEPS

66
kaymant ·

The condition on the derivative give us
(λ+2)x2 - 2λx + 3λ<0
for all x.
For this to happen, the graph of the quadratic f(x)=(λ+2)x2 - 2λx + 3λ must open downwards and be entirely below the x axis. For this we require λ+2<0 (opening downwards) and 4(λ2-3λ(λ+2))<0 (entirely below the axis).
The second condition gives us λ(λ+3)>0 which gives λ>0 OR λ<-3.
So, \lambda \in (-\infty,\,-2)\cap \big((-\infty,\,-3)\cup (0,\,\infty)\big)
which gives λ<-3

11
Mani Pal Singh ·

thank u sir

i was traaped in this and and or [1]

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