simple one

if xp yq = ( x+y )p+q then find dy/dx

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1
Honey Arora ·

xp yq = ( x+y )p+q
Taking log on both the sides
p log x+q log y=(p+q)log(x+y)
Taking derivative
(dy/dx)[(q/y)-(p+q/x+y)]=(p+q/x+y)-p/x
solving
dy/dx=y/x

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