24YUP its a fight going on .............AND NOBODY CARES FOR POOR EUREKA WHO IS SO POOOOOR IN GRAPHING AND WANTS TO LEARN TO QUICKLY FROM HIS FRIENDS.............plzzzz sky atleast u help me,......
1)[x]+[y]=x
2)y=[x]-[x-(1/2)]
3)[x+y-2]-[x-1]=0
where [ ] is GINT
Explain the steps toooo
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21 Answers
1arey i am weaaaaaaak in box function re... see upar!!
or else i wud have loved to help :)
2424Everyone is so busy fighting among themselves that they FORGOT to read this line in question......
""Explain the steps toooo""
1i think abhirup's one is correct... am also getting dat only...
wrong bhi ho skta hai :( [3]
1and my last was wrong only ....
areyyyy saare wrong hi hai :(
1,2,3 sab :(
62this above one will be the answer for part 1 ..
where you will have to consider one thing...
the top most points on the curve is not lthere.. i mean y=+1
11) only the point (0,0) .
[y] = {x}
{x} is only for[0,1) and [y] = all integers .
these two are satisfied for only (0,0).
11How did u get it sky? Why are there dotted lines?
Graph for [x] is 
And graph of [x-1/2] is
DONT MIND THE SCALE
So shouldn't it be the difference obtained by superimposing the graph?
GRAPH (WHICH I HOPE IS CORRECT[3]) IS IN MY NEXT REPLY[4]
62So far good but slight mistake..
YOu said that the only possible solns were
{x}=[y]=0
Now the last interpretation is incorrect
The answer should be (n,0) where n is an integer!