No Akand!
We have done this type quite often yaar....
see as x→∞ GM → AM ............... i.e. wen x is almost infinity AM = GM = HM can b taken!
3√(x+a)(x+b)(x+c) = (x+a + x+b + x+c)/3
==> x + (a+b+c)/3 - x
== (a+b+c)/3
No Akand!
We have done this type quite often yaar....
see as x→∞ GM → AM ............... i.e. wen x is almost infinity AM = GM = HM can b taken!
3√(x+a)(x+b)(x+c) = (x+a + x+b + x+c)/3
==> x + (a+b+c)/3 - x
== (a+b+c)/3
yep ... gordo solved a similar question in a similar fashion ........ or tapan ...... howz life??????