Calculus - sum to infinity

1

First we split the tan inverse part......
11+r²+3/4-1
=11+(r+1/2)(r-1/2)
=(r+1/2)-(r-1/2)1+(r+1/2)(r-1/2)
thus

tan^-1(r+1/2)-tan^-1(r-1/2)

now on puttin further values of r we get pie/2 +tan^-1(1/2)
AM I RIGHT?????????????

62

almost correct.. except the final answer which should have been

pi/2 - tan^-1 1/2

not + (also keep in mind that it is pi not pie :P)

1

heheheeh.....srry....my mistake........

1

ya...thanks lanuk & nishant bhaiyya......

sum to infinity