1i'v tried it much nd does since dis area is constant aftr diffrntiatng it shld be 0......bt plz cn u post the soltn coz m nt reaching nywhre
Q.)The value of ‘a’ fr wch the area of triangle included between the axes and any tangent 2 the curve xay=Лa is constant……..{this is a qstn of arihant difrntial calculus….obj qstn no.26}
Options- a) ½ b)1 c)3/2 d)2
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3 Answers
62The base will be the difference of the x intercepts of the tangent and the normal
NOw the height will be the y; coordinate of the point (h,k) which will be k
So the area is 1/2(int1-int2)k *where int1 and int2 are the x intercepts of the normal and the tangent..
Now try to solve?
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