try it out!!!

evaluate:limit x--->0 ln(1+(sinx)^2) / tan[(ln(1+x))^2]

18 Answers

62
Lokesh Verma ·

dekh.. if we have to find

lim x->0 (tan x)2/tan (x2)

then hwo will you do it?

62
Lokesh Verma ·

@parul

lim x->0 (tan x)2/tan (x2)

=lim x->0 (tan x/x)2/ tan (x2)/x2

now solve :)

simple

use this logic in the first question... original one..

There will be many multiplications and divisions by the same number....

see if that can help :)

1
Parul Kohli ·

Nishant sir plzz make me confirm how u done this?
I am totally confused regarding ur post..........

1
vector ·

kk got da mistke thanx ill delete that one:)

13
deepanshu001 agarwal ·

datz not d ques.....

62
Lokesh Verma ·

The question that you gave in the beginning.. the first post of this thread that is :)

13
deepanshu001 agarwal ·

yeah ...i got it.....nic idea....
ny oder ques of same application....

62
Lokesh Verma ·

think why?

can you give a formal proof?

13
deepanshu001 agarwal ·

think ans wud b 1 for ur ques.....

62
Lokesh Verma ·

is the answer 1?

13
deepanshu001 agarwal ·

nishant bhaiya can u plz explain
woh approx kaise lete hain...??

13
deepanshu001 agarwal ·

plzz...help......

62
Lokesh Verma ·

yes we cant.. that is why i have said.. can you fill in the gaps?

13
deepanshu001 agarwal ·

aise approx kaise le sakte hain ..... havent dun it before ny whr

aise to approx kar karke ques hi change ho jayega ...

62
Lokesh Verma ·

\frac{ ln(1+(sinx)^2)}{ tan[(ln(1+x))^2]}

is this approximately equal to?

\frac{ (sinx)^2)}{(ln(1+x))^2}

which is equal to\frac{ x^2}{x^2}

can you fill in the gaps in the solution?

106
Asish Mahapatra ·

i said i think .. im not sure... trying it anyway...

13
deepanshu001 agarwal ·

using expansions not feasible here....

106
Asish Mahapatra ·

i think u shud just use the expansions of ln(1+x) and tanx.. to get the anser...

Your Answer

Close [X]