try it

In Q3. ,

" q3no of roots of f(x)=0 in[-2] " [7][7] something's missing.

that s not ma doubt it s for ppl on d forum

neways edited

Q2.

Ans : A

I = _-51∫⁵¹ dx/(3 + f(x))

Let x = -t
dx = -dt

I = - ₅₁∫^-51 dt/(3 + f(-t))
= _-51∫⁵¹ dt/(3 + f(-t))

f(y)f(-y) = 9
f(-y) = 9/f(y)

So,

I = _-51∫⁵¹ dy/(3 + f(y)) = _-51∫⁵¹ dy/{3 + ( 9/f(y) )}

2I = _-51∫⁵¹ dy/(3 + f(y)) + {f(y)/3}dy/(3 + f(y))

2I = _-51∫⁵¹ [ 1 + f(y)/3 ] dy/(3 + f(y))

2I = (1/3) _-51∫⁵¹ dy

2I = (1/3)*[51 - (-51)]

So, I = 17

hey 2nd one i am getting 0....

shit came till last and at last step went wrong .

ans 3rd b