1put x=sinθ
we get dx= cosθdθ ,
putting the values
we get this equal to
(sin2θ/cosθ)*cosθdθ = sin2θdθ = (-cos2θ + 1)/2dθ
while i was doin a big prob...........i was stuck in between wher i shud integrate sumthing...........hw do v do tht????????
x2/√1-x2...............dnt scold me if its too easy k???
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5 Answers
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1k thnx.................i got another idea............... just struck.........cant v add and subtract 1????????? thtl be easier....
by d way rohan ur method is easier thnx a lot man.........
1we can also do it by putting √1-x2=t and substitute for dx and x
1Give the necessary and sufficient conditions so that
limx-->0 f (g(x)) = f ( limx-->0 g(x))
1Let f(x) be a quadratic fn. with +ve integral coefficientssuch that for every real a,b b>a a∫bf(x)>0. let g(t)=f''(t)f(t) and g(0) =12
then
a)16such qudrices are possible
b)f(x) has either no real roots or distinct roots
c)f(1)min=6
d)f(1)max=11